Chemical reaction question?
Can someone help me with this problem?
44.3 grams of C6H6 reacts with 122.4 grams of O2. How much CO2 will be produced by this reaction?
2C6H6 + 9O2 -> 6CO2 + 6H2O
44.3 grams of C6H6 reacts with 122.4 grams of O2. How much CO2 will be produced by this reaction?
2C6H6 + 9O2 -> 6CO2 + 6H2O
- 3 years ago
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Best Answer - Chosen by Voters
Number of moles of C6H6 = 44.3/78 = 0.568 mol
Number of moles of O2 = 122.4/32 = 3.825 mol
C6H6 is the limiting reactant because 0.568 mol of C6H6 needs
9/2 x 0.568 = 2.556 mol of O2 to react.
There are 3.825 mol of O2 available. So O2 is in excess.
Hence, the number of moles of CO2 produced = 6/2 x 0.568 mol
......................................… 1.704 mol of CO2
......................................… 74.98 g of CO2
If the experiment is carried out at room temperature, then the volume of CO2 produced = 1.704 x 24 dm3 = 40.90 dm3
Number of moles of O2 = 122.4/32 = 3.825 mol
C6H6 is the limiting reactant because 0.568 mol of C6H6 needs
9/2 x 0.568 = 2.556 mol of O2 to react.
There are 3.825 mol of O2 available. So O2 is in excess.
Hence, the number of moles of CO2 produced = 6/2 x 0.568 mol
......................................… 1.704 mol of CO2
......................................… 74.98 g of CO2
If the experiment is carried out at room temperature, then the volume of CO2 produced = 1.704 x 24 dm3 = 40.90 dm3
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