Resolved Question
Half life question...?
Hi, can someone give me a hand with this, i think i got the right idea, but it don't seem to give me the answer provided.
The radioactive isotope 51Cr is used to evaluate the lifetime of red blood cells.Its t½ = 27.7 days. A hospital laboratory has 80.0 mg of 51Cr. How much of 51Cr is left after 85 days?
Answer given = 9.6mg
by joeyeehu...
Best Answer - Chosen by Asker
All radioactive decay is a first order reaction.
First, you have to calculate the rate constant, k = 0.693/ t1/2
Therefore, k = 0.693 / 27.7
First order equation: ln Ao/A = kt
......................................ln 80/A = (0.693/27.7)(85)
Solving for A will give you the required answer.
Ao = initial mass
A = the mass after time,t
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