What is the molar solubility of Cu(OH)2, Ksp=6.0 x 10^-10?
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Cu(OH)2 ---------------------> Cu2+ + 2OH-
First you let the molar solubility to be x.
therefore the conc of Cu2+ = x
and the conc of OH- = 2x
Ksp = [Cu2+] [OH-]^2
........ = (x) (2x)^2
........ = 4x^3
Hence 4x^3 = 6.0 x 10^-10
x = 5.31 x 10^-4
First you let the molar solubility to be x.
therefore the conc of Cu2+ = x
and the conc of OH- = 2x
Ksp = [Cu2+] [OH-]^2
........ = (x) (2x)^2
........ = 4x^3
Hence 4x^3 = 6.0 x 10^-10
x = 5.31 x 10^-4
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